Write a program in C that prints the first 50 Fibonacci numbers, starting with 1 and 2

To be able to answer this question, you need to understand what a fibonacci number is and how to derive a fibonacci sequence.

A fibnonacci number is any number in a sequence which happens to be the sum of the two preceeding numbers.

This means that the number n in a sequence will be expressed as:

n = (n-1) + (n-2)

For instance, this question states the numbers (1, 2) we should use to start our fibonacci sequence. This means that our sequence will be something like

1
2
1 +2 = 3
3 + 2 = 5
5 + 3 = 8
8 + 5 = 13

This means that if we assign our first two numbers to variables first and second and declare another variable called next, we can go ahead to represent them as.

int first = 1;
int second = 2;
int next = first + second;

In the above case, the next variable becomes 3. As soon as we get that one, we need to find what the next one after 3 will be.

Since we are interested in what is after 3, we will need to reset our first and second variables. You will realize that to get the number after 3, our first variable now becomes 2 and the second variable becomes 3. This gives us:

first = 2;
second = 3;
next = first + second;
=> next = 2 + 3; 
=> next = 5;

The process will then repeated for the variable first to become 3 and second become 5. The next variable becomes 8 which is 3 + 5.

I bet you now know how this works. If you don't, kindly go over it again to understand the steps. We can then go ahead and implement this concept as a C program.

Coding a C program that prints the first 50 numbers

Below is the code in C program that does exactly what we have discussed about.

#include <stdio.h>

/**
 * main - main block
 * Description: Print the first 50 fibonacci numbers, starting with 1 and 2.
 * Numbers must be coma and space separated.
 * Return: 0
 */

int main(void)
{
    int count = 3; /* this is so because the first 2 members have been given already. My loop will therefore begin from the 3rd one */

    long int first = 1, second = 2;
    long int next = first + second;

    printf("%lu, ", first);
    printf("%lu, ", second);

    while (count <= 50)
    {
        /* Let's check if we are at the end of the list, if we are close with a new line */
        if (count == 50)
        {
            printf("%lu \n", next);
         }
         else  /* if we are not at the end of the list, add a comma after the number */
         { 
           printf("%lu, ", next); 
         }

        /* Reset the variables to get the next number */
        first = second;
        second = next;

        /* after resetting the variables, you need to find the next number */
        next = first + second; 
        count++;
    }

    return (0);
}

The output of the above code is:

1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 514229, 832040, 1346269, 2178309, 3524578, 5702887, 9227465, 14930352, 24157817, 39088169, 63245986, 102334155, 165580141, 267914296, 433494437, 701408733, 1134903170, 1836311903, 2971215073, 4807526976, 7778742049, 12586269025, 20365011074

Conclusion

I hope you enjoyed reading this and it made you understand how to solve a problem like this. I would like to hear back from you. Is there anything I missed, or explained wrongly, or something you want me to elaborate more on?

Share with me what you also think. Mind you, I am also learning and your feedback will be valuable to me.

Thanks for reading and I would love to connect personally with you. If you are on Twitter, then you can send me a DM and let's have a good chat.